It can pass compilation and link because no syntax errors happen; but segmentation fault occurs because it lacks exit point, and this leads it to run into others' address space. That's not allowed.
To 码匠: I think so.
To 码匠: I wondered what to do by the program next. That's it.
简单明了，真棒！
同意码匠！
如果您有建设性意见，哪怕只是纠正一个错别字，也请不吝赐教，您留下的姓名和email将会出现在本书前言的致谢中。再次感谢您的宝贵意见！